SOMEONE PLEASE HELP ME WITH MATH!!

Henrietta · Post by **Henrietta** » 7/11/2003, 7:43 pm

OMG...my final is tomorrow and I need help w/ intermediate algebra so bad. If you can help, please do!!!! I thought the damn online tutoring place stayed open till 9...no no no...they aren't open at all on Fridays!

Penguin Josh · Post by **Penguin Josh** » 7/11/2003, 8:01 pm

what parts do you need help with, what are you still doing in school :huh:

Henrietta · Post by **Henrietta** » 7/11/2003, 8:44 pm

it's just one class that continued over into summer.

I need help with some log problems and some square root problems.

superrgirll · Post by **superrgirll** » 7/11/2003, 8:45 pm

what are the problems?

Penguin Josh · Post by **Penguin Josh** » 7/11/2003, 8:47 pm

yeah show the problems and we can do them

Henrietta · Post by **Henrietta** » 7/11/2003, 8:51 pm

ok..it's kinda hard w/ these keys though...

rationalize the domain...

4/5-(*5)

(*) means that is under the square root symbol...

AND

(*x)=(*x-8)+2

to begin with

Penguin Josh · Post by **Penguin Josh** » 7/11/2003, 8:58 pm

I'm not in algebra again until september sorry I was in geometry for my fresman year of high school

Henrietta · Post by **Henrietta** » 7/11/2003, 9:07 pm

LMAO...well I don't think geometry is going to help. But good luck w/ that...cause it's harder than hell imo.

Penguin Josh · Post by **Penguin Josh** » 7/11/2003, 9:09 pm

well i dont have to do it again until... IDK

Corey · Post by **Corey** » 7/11/2003, 9:29 pm

SpclAgntCass wrote:(*x)=(*x-8)+2

x = x - 8 + 4(*x-8) + 4
x = x - 4 + 4(*x-8)
4(*x-8) = 4
16(x-8) = 16
16x-128 = 16
16x = 144
x = 9

... i'm not sure that is the entire domain... but it's one of the answers

Penguin Josh · Post by **Penguin Josh** » 7/11/2003, 9:34 pm

were did u get the four

Narbus · Post by **Narbus** » 7/12/2003, 1:50 am

SpclAgntCass wrote:ok..it's kinda hard w/ these keys though...

rationalize the domain...

4/5-(*5)

Ok, I'm not totally sure this is right, but here's the idea. Domain's are simply where the answer is a real number. To find a domain, you have to have an "x" in there, somewhere, so I'm assuming that what you've given here is actually the domain, and we have to put it in rational terms (*5 is not a rational number; it neither repeats nor terminates).
so, we just need to find a real value for the above expression. Multiply the whole thing by 5. (4/5) * 5 = 4, and the sqrt(5) * 5 = 5, by way of what a square root is. So we end up with 4-5, which leaves with with -1. The rationalized domain is -1.

AND

(*x)=(*x-8)+2

to begin with

Are we supposed to solve, or find the domain? Corey solved it, and the domain (the values of x where the solution to the problem is real) is x<=8, I believe.

Corey · Post by **Corey** » 7/12/2003, 11:04 am

Josh wrote:were did u get the four

I squared both sides

Corey · Post by **Corey** » 7/12/2003, 11:04 am

Narbus wrote:Are we supposed to solve, or find the domain? Corey solved it, and the domain (the values of x where the solution to the problem is real) is x<=8, I believe.

Don't you mean x >= 8?

Johnny · Post by **Johnny** » 7/12/2003, 3:54 pm

math was my worst subject on school :freak:

superrgirll · Post by **superrgirll** » 7/12/2003, 5:05 pm

i have no clue what the answer is. i am so screwed for math next year.

Narbus · Post by **Narbus** » 7/12/2003, 9:04 pm

Corey wrote:Don't you mean x >= 8?

Yes, actually I do.

Henrietta · Post by **Henrietta** » 7/12/2003, 11:06 pm

Corey was right, the answer was 9.

Thanks for the help guys!

committed · Post by **committed** » 7/13/2003, 7:19 am

math is easy fo sheezy so breezy