ClumsyMonkey.net

OMG...my final is tomorrow and I need help w/ intermediate algebra so bad. If you can help, please do!!!! I thought the damn online tutoring place stayed open till 9...no no no...they aren't open at all on Fridays!

what parts do you need help with, what are you still doing in school :huh:

it's just one class that continued over into summer.

I need help with some log problems and some square root problems.

what are the problems?

yeah show the problems and we can do them

ok..it's kinda hard w/ these keys though...

rationalize the domain...

4/5-(*5)

(*) means that is under the square root symbol...

AND

(*x)=(*x-8)+2

to begin with

I'm not in algebra again until september sorry I was in geometry for my fresman year of high school

LMAO...well I don't think geometry is going to help. But good luck w/ that...cause it's harder than hell imo.

well i dont have to do it again until... IDK

SpclAgntCass wrote:(*x)=(*x-8)+2

x = x - 8 + 4(*x-8) + 4
x = x - 4 + 4(*x-8)
4(*x-8) = 4
16(x-8) = 16
16x-128 = 16
16x = 144
x = 9

... i'm not sure that is the entire domain... but it's one of the answers

were did u get the four

SpclAgntCass wrote:ok..it's kinda hard w/ these keys though...

rationalize the domain...

4/5-(*5)

Ok, I'm not totally sure this is right, but here's the idea. Domain's are simply where the answer is a real number. To find a domain, you have to have an "x" in there, somewhere, so I'm assuming that what you've given here is actually the domain, and we have to put it in rational terms (*5 is not a rational number; it neither repeats nor terminates).
so, we just need to find a real value for the above expression. Multiply the whole thing by 5. (4/5) * 5 = 4, and the sqrt(5) * 5 = 5, by way of what a square root is. So we end up with 4-5, which leaves with with -1. The rationalized domain is -1.

AND

(*x)=(*x-8)+2

to begin with

Are we supposed to solve, or find the domain? Corey solved it, and the domain (the values of x where the solution to the problem is real) is x<=8, I believe.

Josh wrote:were did u get the four

I squared both sides

Narbus wrote:Are we supposed to solve, or find the domain? Corey solved it, and the domain (the values of x where the solution to the problem is real) is x<=8, I believe.

Don't you mean x >= 8?

math was my worst subject on school

i have no clue what the answer is. i am so screwed for math next year.

Corey wrote:Don't you mean x >= 8?

Yes, actually I do.

Corey was right, the answer was 9.

Thanks for the help guys!

math is easy fo sheezy so breezy